Someone receives a bonus of 240 yuan, including 2 yuan, 5 yuan and 10 yuan, a total of 50 pieces, of which 2 yuan and 5 yuan are as many, then 2

5 thoughts on “Someone receives a bonus of 240 yuan, including 2 yuan, 5 yuan and 10 yuan, a total of 50 pieces, of which 2 yuan and 5 yuan are as many, then 2”

  1. For 2 yuan, there are X Zhang, then 5 yuan also has X Zhang, so 10 yuan will have 50-2x Zhang
    The Known Known is 240
    has 2x 5x 10 (50-2x) = 240
    The X = 20
    So there are 20 pieces of 2 yuan, 20 pieces of 5 yuan, 10 yuan for 10

  2. There are X Zhang with 2 yuan 5 yuan, and 10 yuan with 50-2X,
    (2 5) x 10 (50-2x) = 240
    n So 10 yuan is 50-20-20 = 10.
    The calculation method: 2 yuan is as many as 5 yuan, and it is seen as 7 yuan
    10-240) ÷ (10 × 2-2-5) = 20 photos
    So 10 yuan is 50-20-20 = 10 photos

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